The specific heat capacity of water is 4,200 J/(kg*degree). The energy required to move 1 cubic meter of water from 20 degrees to 60 degrees is 4200*1000*(60-20) J = 16.8*10. ~7 J, 1 J = 1 watt second, so the energy required is (16.8*10~7)/1000/3600=46.67 kilowatt hours. Because it's half an hour, the power is 46.67/0.5=93.34 kilowatts
Five kilowatts of hydroelectric power How many cubic meters of water does the machine need in one hour?
1 cubic meter of water requires 93.34 kilowatts when It is heated from 20 degrees to 60 degrees in 30 minutes. Dear ~ The specific heat capacity of water is 4200 J/(kg*degree). The energy required to go from 20 degrees to 60 degrees is 4200*1000*(60-20) joules = 16.8*10. ~7 joules, 1 joule = 1 watt second, so the energy required is (16.8*10~7)/1000 /3600=46.67 kilowatt hours. Because it's half an hour, the power is 46.67/0.5=93.34 kilowatts.
It dependsend also of the fall (height) of the water. Suppose the head is H (m), the flow rate is Q (m3/h), the power is P (kW) and the density of water is d (1000kg/ m3), the acceleration of gravity g = 10m/s2, taking into account the conversion efficiency μ, the relevant formula is: P = μdgHQ/3.6, if: μ=0.6, P=5kW, d= 1000kg/m3, H = 2m, Then Q = 3.6P/(μdgH) = 3.6x5/(0.6x1x10x2)= 1.5m3/h.
That is, when the generator has a height difference of 2 meters and a conversion efficiency of 0.6, the required water flow is about 1.5 meters cube per hour.