Concerning the production of energy by water wheel, there is some data. Anyone in the know can tell

Introduction Concerning the production of energy by water wheel, there is some data. Anyone in the know can tell me how to do it. THANKS ! The height of the water is unknown. I fear that the water height will not reach 2 meters (no authorization will be given to build

Concerning the production of energy by water wheel, there is some data. Anyone in the know can tell

Water height is unknown.

I fear that the water height will not reach 2 meters (the construction of the dam will not be approved).

Even if the water height reaches 2 meters and the flow rate is 0.35 cubic meters/second, the limit of power that the potential energy of the water can provide is only:

mgh=350 *9.8*2=6860 watts< /p>

Considering that the conversion efficiency is less than 30%, the actual power obtained is: 6860*0.3=2058 watts.

No commercial significance.

If only the energy of the water flow is converted into electrical energy, the power limit value contained in the energy of the water flow is approximately:

0.5 mvv=0.5*500*0.75*0.75=140 watts.

It would be pretty good if you could do 30 watts.

As a hobby this is debatable; for practical reasons it is worthless.

The potential energy of a ton of water per kilometer

~~~~~~~~~~~P=9.8gQH

P is la output power, The unit is kilowatt;

9.8 is the acceleration of gravity;

g is the efficiency, which can be simply regarded as 0.8~0.9 for a general power plant;

Q is the flow rate, unit: cubic meters/second;

H is the water height, also called height difference,

P=9 .8*0.85*0.4*100=27.2KW.

It is recommended to purchase a hydroelectric generator with a production power of 30KW. Electricity production is 27 kilowatt hours per hour~~~~~~~~~~

The above formula is correct, but the answer is too different

P =9.8GQH= 9.8*0.8*0.6*100=470KW. I don't know how to calculate 27.2kw per 100 meters of water height. Even a flow rate of 0.4 is not that small in terms of efficiency, small unit generators usually take 0.8, and turbines. also take 0.9. Full Take 0.8. If it is an impact type, the yield is lower by2 points, so take 0.8. For mixed flow, take 0.82. For the positive solution, I choose impact 400KW or 500KW. 500 for this station. 500 degrees in one hour

1 ton=1000kg, the potential energy of a ton of water per meter: 1000kg*9.8m/S2=9800N(Newton< strong>)< /strong>

Calculated based on a water level 100 m high, the work done by each ton of water is W=9800N*100m=980000J (Joules )

And one kilowatt hour of electricity (1kW.h) is equal to 3600000J (3.6MJ), so each ton of hydroelectricity generates 980000/3600000=0.27 kilowatt hour of electricity

If the water level is lower than 100 meters, its value will be reduced proportionally. If the conversion efficiency of the generator is considered to be around 50%, its value will be lower.

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