It is known that the water entering the vortex machine per second is 6,000 liters.
We can then see that the gravitational potential energy work of water is mgh=6000×10×100=6×10^6 J Joules
Because it is the unit of time, < /p>
that is, the power is 6 MW,
4.5/6=3/4
< p>It is obvious that the efficiency of the system is 75%,4.5/0.95=180/19< /p>
19×6/180=0.6333333
That is, the efficiency of the turbine is 63.33%
Understand the translation: The turbine uses 63.33% of the potential energy of water, then with an efficiency of 95% the energy of the generator is converted into electricity, with a power of 4.5 MW.
The level is limited, please do not adopt it if it is incorrect.
(1) The output power of the generator is: P1=
50%×mgh×75% |
t |
(2) The power lost on the transmission line is: P loss = 5% P1 = I22R,
The solution is: I2 =
| < /tr >
|
According to P1=U1I1: I1=
P1 |
U1 |
4.05×104 |
500 |
Then, the turns ratio of the primary and secondary coils of the step-up transformer is:
n1 |
n2 |
I2 |
I1 | < /tr>
14 |
81 |
The power obtained by the user is: P4 = P3=95%P1,
Then the current on the user side is: I4 =
P4 |
U4 |
95%×4.05×104 |
220< /td>< /tr> |
Then the turns ratio of the primary and secondary coils of the step-down transformer is:
n3 |
n4< /td> |
I4 |
I3 |
175 |
14 |
25 |
2 |
Answer: (1) Power generator output is 4.05 × 104 W
(2) The boost turns ratio is 14:81 and the buck turns ratio is. 25. :2.