If the starting intervals are the same, the distance between two adjacent cars in the same direction is the same
Suppose this distance is 1
The sum of the speeds of the car and Xiao Zhang is 1/5
The sum of the speeds of the car and Xiao Wang is 1/6
The sum of the speeds of the two cars is 1/4
The sum of the speeds of Xiao Zhang and Xiao Wang is 1/ 5+1/6-1/4=7/60
The sum of the speeds of Xiao Zhang and Xiao Wang is 7/60÷(1/4÷2)=14/15 of the speed of the tram
It takes two people to meet: 70÷14/15=75 minutes
Math Olympiad Problem (Part 6) Masters, please help~~
Solution: Set the distance traveled by the tram in 1 minute to 1
< p>Each tram meets an oncoming tram every 6 minutes, which means the distance between the two trams is 12.Xiao Zhang meets an oncoming tram everytes the 8 minutes, which means that the distance covered by Xiao Zhang in 8 minutes = tram ride (12-8) = 4
Similarly, the distance covered by Xiao Wang in 9 minutes = (12-9) = 3
Then Xiao Zhang's speed is 4/8, which is 1/2, Xiao Wang's speed is 3/9, which is 1; / 3
The total distance is 45
So 45/(1/2+1/3) = 54 minutes
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11. How much does the rest cost if found directly?
A: (1-2/5)*(1-2/3)*(1-2/ 5)a
B: (1-2/3)*(1-2/5)*(1-2/3)b
A:B=2:1:a:b=9:5
12. For the trams to pass each other every 4 minutes, we can find out by drawing a continuation diagram:
Both places must start at the same place. and 8 minutes apart
Suppose the entire trip is 1, then:
We can know that the speed of the tram is 1/56, then the distance between the two oncoming trams are 1/7
At that time, Xiao Zhang I met an oncoming tram every 5 minutes
That is: 1/7 of the distance was covered by the tram and Xiao Zhang in 5 minutes La Xiao Zhang's speed can therefore be calculated: (1/ 7)/5-1/56=3/280
Similarly: Xiao Wang meets an oncoming tram every 6 minutes
Then the speed of Xiao Wang: (1/7)/6-1/56=1/168
Then the time that Xiao Zhang and Xiao Wang walked when they meet on the path is
1/(3/ 280+1/168)=840/14=60 points
I think I am not the first to explain this idea and this question here
But I hope the poster can see it clearly
Consider it appropriate
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