The unit of power for wind energy is W/m2 (Watts per square meter). When the average annual wind speed is 7 m/s, the wind power is 400 W/m2. wind turbine, the larger the swept surface. The larger it is (C=R2), the larger the swept surface, the more wind energy it absorbs and the more electricity it generates.
Simply put, when wind speed is constant, the longer the blades, the more electricity is generated. Of course, you shouldn't stress it for too long, as problems can arise and it can be easily damaged.
The reason they are thin is to reduce the mass of the blades, otherwise they would be too heavy to be blown by the wind and produce electricity.
Please do not copy and paste too much. The key is whether the pasted content is relevant. LZ asks about wind turbine blades, not co turbine bladesmpressors, as you mentioned.
Wind turbine blades are determined based on factors such as the wind turbine's design power rating, wind turbine's rated wind speed, and local wind density.
If the diameter of the turbine of a wind turbine is D
Then its swept surface S = ∏D^2/4
The surface crossed per unit of time The mass of the wind, that is to say the flow rate of the wind, is Q = ρSV = ρ∏VD^2/4 V is the speed of the wind
According to the theorem of kinetic energy, there is a wind energy density< /p>
P1 = 0.5mV^2 = (ρ∏VD^2/4)V^2/2 = ρ∏D^2*V^2 /8
Then there is a wind energy coefficient Cp, which is the wind energy coefficient Cp obtained by the wind wheel from Ek. The percentage of wind energy that can be captured represents the total wind energy.
Therefore, the theoretical energy production of wind energy
P = Cp* P1
Before designing the EOlink, it is necessary to The design wind speed V and air density ρ can be obtained by long-term observation of wind speed and air density in the wind field. The design Cp is related to the tip speed ratio, and the optimal value is generally selected. Therefore, the required theoretical diameter of the wheel can be recalculated.