24 hours multiplied by 500 W equals 12,000 W or 12 kW.
I assume the poster is doing a technical inspection.
How many wind speeds can there be an average of 7-8 m/s per day?
We assume that in general areas, there are only 4-5 hours, then you need about 3 kW fan, which can provide 12 kW to 15 kW per day, at provided that you need to make sure that there is so much wind every day.
If the wind speed is very good and is more than 7 m/s for 12 hours or more every day, then you can choose 2 kW fan.
As for the battery, it is recommended to choose at least 10 12V 150 Ah batteries, this can basically store 15 kW of electricity, which can last a windless day. If the number of days to be covered increases, you. can double the battery.
Although your maximum power does not exceed 600w, it is still recommended tochoose a 2kw inverter, after all, the difference is only a few dollars.
Power generation process:
Fan blade---gear box--- DC motor---rectifier bridge (polarity protection)----Battery
Principle:
The wind turns the blades (similar to the blades of an electric fan ) to drive the gearbox so that the speed of the DC motor exceeds the rated speed. At this time, the motor will generate the voltage will be equal to the motor operating voltage, generally 12V or. 24V, because the battery is usually at these voltages.
Difficulty:
To make a gearbox, you must calculate the transmission ratio. For example: the rated speed of the motor is 3000, the fan blade rotates 10 times per minute, and the motor end reaches 3000 rpm. At present, the transmission ratio is 1:300.
The above dataare obtained from the small power manual generator model I made and are for reference only.