The wind-solar hybrid street light is a public lighting system that uses solar and wind energy for power supply. It uses photovoltaic solar panels and wind turbines as energy sources and stores energy via energy storage devices for nighttime lighting. This type of street lighting system is green, environmentally friendly, energy-saving, efficient, reliable and stable, and is widely used in urban roads, rural roads, parks, squares and other places.
First of all, hybrid wind and solar street lights use photovoltaic solar panels as the main source of energy. Photovoltaic solar panels can convert sunlight into electrical energy and store electrical energy through photovoltaic power generation systems. This source of energy has the advantages of being free, non-polluting and renewable, and canut effectively reduce dependence on traditional energy, energy consumption and environmental pollution.
Second, wind-solar hybrid street lights also use wind turbines as auxiliary power sources. Wind turbines can convert wind energy into electrical energy and store electrical energy through wind power generation systems. Compared with photovoltaic solar panels, wind turbines can provide stable energy supply at night or in rainy weather, ensuring the normal operation of street lights.
In addition, wind-solar hybrid street lights are also equipped with energy storage devices to store electrical energy converted from solar and wind energy. Energy storage devices generally use lithium batteries or lead-acid batteries, which have the characteristics of one ofHigh energy density, long life and low self-discharge rate. Through the energy storage device, excess electric energy from photovoltaic power generation and wind power generation during the day can be stored for night lighting use, thereby achieving efficient use of energy.
The installation and maintenance of wind-solar hybrid street lights is also relatively simple and convenient. Since there is no need to connect it to the power grid or lay cables, construction costs and time can be reduced. At the same time, because photovoltaic solar panels and wind turbines have a long service life and low maintenance costs, the maintenance costs of wind-solar hybrid street lights are also relatively low.
In short, the wind-solar hybrid street light is a systemgreen and environmentally friendly public lighting that uses solar and wind energy for power supply. It has the advantages of energy saving, high efficiency, reliability and stability, easy installation and maintenance, etc. It can effectively reduce energy consumption and environmental pollution and provide sustainable solutions for urban and rural lighting.
Read the short article and answer the questions. The wind-solar hybrid street lighting system is equipped with both wind turbines and solar panels. When the wind blows, the wind turbine produces electricity. Yes.
Answer:
(1) B
(2) Electromagnetic induction; electricity
(3) 80
(4) 6.0
(5) 14.4
(6) 7, 98
Ideological analysis:
< p>Anatomy of test points: tested classification of energy, electromagnetic induction phenomenon and its energy conversioni.e., calculation of electric power and electric work, and also tests the candidates' application ability.Ideas for solving questions:
(1) Determine the answer based on the classification and characteristics of energy;
(2) Analyze the phenomenon of electromagnetic induction and its energy conversion;
(3) First find the output power of the 0.5 square meter solar panel, and then use = ηP to calculate the electricity generation;
(4) According to the wind power generation power, the power is proportional to the cube of the wind speed: = kv3, first find the constant value k from the known data in the table, and then find the wind speed when the output power is 50W;
(5) Combine the meaning of the question, it can be seen that in order to extend the battery life, the usage time discharges up to to the remaining 20% and stope the production of electrical energy, that is, the electrical energy consumed does not exceed (1- 20%), W=UIt×(1-20%), then calculate according to the calculation.
(6) Calculate the electrical energy consumed based on W=Pt, then calculate the amount of coal that must be burned in a month based on m=Wβ.
Answer process:
Solution:
(1) Solar energy and wind energy are renewable energy sources;
(2) Wind and solar power generation. The machine generates electricity based on the principle of electromagnetic induction and converts wind energy into electrical energy when operating;
(3) From the data in the table, it can be See that the output power of a solar panel per square meter is 1000W and the area is 0.5. The output power of a one square meter solar panel is P = 1000 W/m2 × 0.5 m2 = 500 W, so the power generated is = ηP = 16% × 500 W = 80W ;< /p>
(4) When the wind speed reaches the maximum, the wind force. The output power of electricity generation reaches the maximum. Because the wind power generation power is proportional to the cube of the wind speed, we can know: =kv3, then from the table data: when =12 m/s, the output power is =400W, then 400W=k×(12m /s)3?①
When the output power is =50W, then
50W=k×v3?②
Solve ①② to obtain: v= 6.0 m/s.
(5) The battery has a longer lifespan. The maximum power consumption during use is W=UIt×(1-20%)=?UIt×80%, obtained from p=w/. t,
p>
(6) W＝ptotal t=1000×0．07kW×10h=700kW?h
m=30×Wβ= 30×700kW?h×380g/ (?kW·h)=7.98×106g=7.98t．
Rule Summary:
The key to solving this problem is: (1) Master the relationship between the output power of solar panels and the generated power; (2) Understand correctlyt the; power of wind energy Proportional to the cube of wind speed (3) Skillful use of formulas such as P=W/T?W=UIt.
The difference between wind turbines and wind-solar hybrid generators
(1) Solar energy and wind energy are sources of renewable energy, then choose B;
(2) Wind turbines produce electricity based on the principle of electromagnetic induction. When wind energy is used to generate electricity, the mechanical energy (wind energy) is converted into electrical energy;
(3) The power P of the solar energy absorbed by the panel =1000W/m2×0.5m2=500W,
The output power of the solar panel P′=16%×500W=80W;
(4) According to the meaning of the question ,
| S large | |||||||||||||||||||||||||||||||||||||
| < /tr>< /table>=
| P |
| v3 |
So the wind speed v =
| 3 |
P large | | ||
| 3 |
| |
（5）∵P=UI，
∴I=
| P |
| U |
| 100W |
| 12V |
Discharge to residual power when in use use Stop output power at 20%, discharge quantity Q=150Ah×(1-20%)=120Ah,
∵I=
| Q | ||
| t |
| Q |
| I |
| 120Ah | ||
|
So the answer is: (1) B; (2) electromagnetic induction; (3) 80; (5)
Read the passage; and answer the questions: The complementary wind-solar public lighting system (0A and B are respectively physical objectsand circuits) is equipped with both wind turbines and solar cells.
Wind-solar complementary energy production The system can be used in the following three ways depending on the changes in energy wind and solar radiation. Operation in two modes: the wind turbine only powers the load; the photovoltaic power generation system only powers the wind turbine load; and photovoltaic energy productionThe system jointly powers the load.
Wind-solar hybrid power generation has the following advantages over wind power generation or photovoltaic power generation alone:
●Using the complementarity of wind power and solar power, relatively stable output can be achieved, and the system has higher stability and reliability performance;
● While guaranteeing the same power supply, theenergy storage battery capacity can be significantly reduced [5]; > ●Through reasonable design and adaptation, it can essentially be powered by hybrid wind and solar power generation systems, with little or no need to activate backup power sources such as generators diesel, etc., which can generate better social and economic benefits. .
(1) Wind turbines produce electricity based on the principle of electromagnetic induction. When wind energy is used to generate electricity, mechanical energy (wind energy) is converted into electrical energy.
Solar energy and wind energy are renewable energy sources;
(2) It can be seen from the picture that there is power from output when the wind speed is V1~Vh, so the wind speed range for the wind turbine to generate electric power is V1~Vh ;
(h) According to the meaning of the question,
| Four middle fingers | ||
|
| four |
| vh |
So the wind speed v=
| h | Four
| |
| Big Four |
| She did it W |
(Her)∵four=it I,
∴I =
| Four |
| It |
| h6W |
| 12V |
when used Discharge until '2% remains and stop the production of electrical energy The discharge quantity Q=15 itAm×(1-2 it%)=12 itAm,
∵I=
| Q |
| Like |
∴Discharge time:
For example=
| Q | ||
| I |
| 12h | < /tr>||
|