How to determine the height of the room based on the number of air changes

Introduction Room height value based on air exchange rate method 1. The air exchange rate in the oil storage room of the diesel generator room is ≧ 5 times/h. 2. The number of air changes in the substation room is 5-8 times/h, and the number of air changes in the powe

How to determine the height of the room based on the number of air changes

1. The number of air changes in the oil storage room of the diesel generator room is ≧5 times/h.

2. The number of air changes in the substation room is 5-8 times/h, and the number of air changes in the power distribution room is 3-4 times/h.

3. The number of air changes in the refrigeration machine room is 4-6 times/h.

4. The number of air changes in the fuel oil boiler room and direct fuel fire engine room is ≧ 3 times/h, and the number of air changes in accidental ventilation is ≧ 6 times. /h.

5. The number of air changes in gas boiler rooms and direct-fired gas engine rooms is ≧6 times/h, and the number of air changes in accidental ventilation is ≧12 times/h.

6. The ventilation volume of the oil depot should be ≥6 air changes/h; the ventilation volume of the oil pump room must bebe ≥12 air changes/h when calculating the air changes of both; , the height of the room can generally be 4 m;

7. The ventilation volume between underground daily fuel tanks should be ≥3 hours/h.

8. The gas pressure regulating and metering room should be equipped with a continuous exhaust system and the ventilation volume should be ≥ 3 air changes/h, the accidental ventilation volume should be ≥ 12 air changes 'air/hr; .

9. The laundry room can be estimated based on the following air change times: The air change rate for production rooms is 20 to 30 times/h. Where there are local ventilation installations, the overall extract air rate. is 5 times/h. The ventilation frequency is 2 to 3 times/h; the ventilation frequency of auxiliary rooms is 15 times/h. Living spaces must comply with relevant specifications.

10. LPublic toilets should be ventilated 10 to 15 times/hour; residential bathrooms and boiling water rooms should be ventilated 5 to 10 times/hour; For air-conditioned hotel bathrooms, the exhaust air volume should be based on the fresh air volume in the room 80%~90%.

11. The smokehouse should be equipped with a mechanical exhaust and the exhaust volume should be selected based on 10-15 air changes/h.

12. The elevator machine room can use mechanical ventilation or refrigeration (with its own cold source air conditioner) to cool in summer. The volume of air used for ventilation and cooling can be determined by the air change method. , which is generally 5 to 15 times/h.

13. The ventilation of the darkroom should adopt mechanical exhaust and natural air intake ventilation methods, and the exhaust volume should be ≥5 changemair inlets/h. The air outlet should be located near the pool. The air inlet should use blackout blinds and the wind speed through the blinds should be <2 m/s.

14. The number of air changes in underground storage rooms and bicycle garages is 2 to 4 times/h.

15. Underground garage: Install a mechanical exhaust system. The exhaust system is adjusted according to the fire protection zone. The exhaust volume is 4 times/h (based on a floor height of 3.0 meters). Use low noise fans and no noise reduction measures.

16. The underground equipment room is equipped with a mechanical exhaust system: 5 times/h in the water pump room, 8-10 times/h in the substation and 4 times/h. h in the low electrical machine room

I want to install a 1kW wind-solar hybrid power generation system. Can it be combined witha 500W solar panel and a 500W wind turbine?

Ⅰ. (1) The pressure of the device on the fishing boat:

F=G=mg=40kg×10N/kg=400N,

The pressure on the fishing boat :

p= FS=

400N
0.32 m2
=1250Pa;

(2) Electrical energy can be generated in 1 hour of normal operation:

W=Pt=500×10-3kW×1h=0.5kW?h;

(3) 1000 fishing boats normally generate electricity for 8 hours:

W total = 1000 × 500 × 10-3 kW × 8 h = 4000 kW? h,

Reduced CO2 emissions:

m′=W total×(0.42kg/kW?h-0.03kg/kW?h)=4000kW?h×0 .39kg/kW?h=1560kg;

p>

Ⅱ. (1) Electrical energy released by the batteryie:

W″=12V×500A?h×(90%-20%)=12V×500A×3600s×(90%-20%)=1.512× 107J;

Duration required:

t=

W″
P
=
1,512×107J
50W
=302400s=84h;

(2) Panel area:

S=′

< tr >< /table>=
P Electric
Radius ηP
36W
240W/m2×15%
=1m2.

Answer: Ⅰ. (1) The pressure on thefishing boat is 1,250 Pa;

(2) Normal operation can generate 0.5 kW/h of electrical energy for 1 hour

(3) Normal energy production; for 8 hours will reduce CO2 emissions by at least 1,560 kg;

II. (1) It takes 84 hours to charge the battery from 20% to 90%;

(2) The area of ​​the solar panel should be at least 1 m2.

The power of the two batteries is: 12*200*2=4800W. In order not to damage the battery, it is best to reserve 20% of the power and not use it. The conversion rate of the inverter is generally 90%. Once two 200Ah batteries are fully charged, the power that can be produced is: 4800 x 80% x 90% = 3456W. It can drive a 100W load for 34 hours, a 200W load for 17 hours or 1000W charge for 3.4 hours. (3456 divided by charging power equals usage time)

The output ofEnergy of a wind turbine is a bit difficult to calculate at the rated wind speed, it can generate 500W of electricity in an hour. If the solar panel is 500W, it can generate 2000-2500W of electricity per day when there is enough sunshine (it cannot produce much electricity even if there is sunshine on the day). morning and evening, and is generally calculated as 4 to 5 hours per day). ). If it is cloudy, very little energy will be generated.

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