Question 1: How to calculate the number of kilowatt hours of electricity generated by photovoltaic power generation per day? A 1 KW module benefits from efficient sunlight for 6 hours and does not take into account losses, or 6 kilowatt hours of electricity. per day. The loss of independent systems is generally 30%. 6*0.7=4.2 kW/h. You must take into account the intensity of solar radiation. 6 hours of effective sunshine refers to the intensity of sunshine. The so-called effective hours of sunshine refer to the intensity of the radiation.
Example:
If the unit of radiation is cal/cm2, then:
Maximum sunshine hours = radiation × 0.0116
0.0116 is the conversion factor to convert radiation (cal/cm2) to maximum sunshine hours:
Definition of maximum sunshine: 100 mW/cm2=0.1 W /cm2
1cal=4.1868 J=101868Ws 1h =3600s
Then: 1cal/cm2=4.1868Ws/cal(3600s/h×0.1W/cm2)=0.0116hcm2/cal
For example: Suppose a certain place The annual horizontal radiation is 135 kcal/cm2 and the radiation on the square surface is 148.5 kcal/cm2, then the annual maximum sunshine hours are:
148500×0.0116=1722.6 h, the daily maximum sunshine hours are
p>
1722.6÷365=4.7h
Question 2: Concerning the calculation of the annual production of photovoltaic energy, an estimate An approximate estimate can be made as follows: Total electricity production (kWh) = effective surface area of photovoltaic cells (square meters) * annual average intensity of total solar radiation (w/square meters) * annual effective sunshine duration (hours) * component efficiency (silicon cells are typically 15%) * system efficiency (Typically 75% is acceptable.) If you want to calculate carefully, you should use aspecial software.
Question 3: How is photovoltaic energy production calculated? Photovoltaic generator machine capacity * equivalent sunshine time = initial total energy production.
Total initial energy production * panel efficiency = panel energy production
The unit of equivalent sunshine time is hour/day. Therefore, the calculated electricity production of the square grid is the daily average electricity production. To calculate the annual electricity production, it must be multiplied by 365.
The equivalent sunshine duration can be obtained using "the average annual amount of solar radiation" / 1000W.
Square network efficiency = (1-cable loss)*equipment efficiency*transformer efficiency*(1-dust impact)
< p> The efficiency of square lattice is generally 70%~80%, maybethat 70% is not that low, I don't remember exactly. How far should you go? You can apply to a design institute with new energy qualifications.
Question 4: How to calculate the actual energy production of photovoltaic modules? Actual power of photovoltaic modules * effective lighting duration * total system efficiency (usually refers to the efficiency loss subtracted) = actual power generation
Question 5: How is the production of photovoltaic energy calculated? 100 square meters can be installed with battery panels of around 15 kilowatts, and the inverter is selected according to the capacity of the battery panel.
Average electricity production is about 60 degrees per day!
Question 6: How to calculate the electricity production of a photovoltaic plant? The annual electricity production of'a photovoltaic plant has a great relationship with the capacity of the system installed in the power supply? station and local average annual sunshine hours. The specific calculation The formula is as follows for reference: annual electricity generation = system capacity * average annual sunshine hours * 0.8 * 365; (This answer is referenced by solar energy expert Guangdong Sunku New Energy)
Question 7: How to calculate the daily energy output of solar power generation For estimate the energy production of. the photovoltaic power generation system, you need to know the system installation Local effective sunshine hours, system efficiency and system installation capacity.
For example, for a 1000W grid-connected photovoltaic system, the installation location is Beijing, the effective sunshine duration is 4 hours, and the eefficiency of the grid-connected photovoltaic system is about 80%, so the daily power system production calculation formula = effective module installation capacity Hours of sunshine system efficiency = 1,000 × 4 × 0.8 = 3,200 Wh, or approximately 3.2 kilowatt hours of electricity.
Question 8: How is the electricity production of a photovoltaic plant calculated? 5 points Are you referring to how the power rating of a PV plant is calculated?
Capacity of the photovoltaic field * equivalent duration of sunshine = total initial electricity production.
Total initial energy production * panel efficiency = panel energy production
The unit of equivalent sunshine time is hour/day. Therefore, the calculated electricity production of the square grid is the daily average electricity production. To calculate the production of electricityannual ctricity, it must be multiplied by 365.
The equivalent sunshine duration can be obtained using "the average annual amount of solar radiation" / 1000W.
Square network efficiency = (1-cable loss)*equipment efficiency*transformer efficiency*(1-dust impact)
< p> The efficiency of square array is generally 70%~80%, maybe 70% is not that low, I don't remember exactly. How far should you go? You can apply to a design institute with new energy qualifications.
Question 9: Calculate the energy production of solar panels and the panel area required for a 1 MW rooftop photovoltaic plant.
The area of a 235W polycrystalline solar panel panel is 1.65*0.992=1.6368O, 1MW requires 1000000/235=4255.32 batteries, the total number of battery panels Area 1.6368*4255.32=6965O
Theoretical annual energy production = annual average total solar radiation * total battery area * photoelectric conversion efficiency = 5555.339* 6965*17.5%
< p> =6771263.8MJ=6771263.8*0.28KWH=1895953.86KWH=1.896 million degrees
Actual efficiency of energy production
The DC power produced by the solar panel is the rated power of the solar panel. Solar panels operating on site often do not meet standard test conditions and the allowable output deviation is 5%. Therefore, the influence coefficient of 0.95 should be considered when analyzing the power output of solar panels.
As the temperature of the photovoltaic module increases, the output power of the f:l group will decrease. For crystalline silicon modules, when the temperature inside the photovoltaic module reaches 50-75°C, its poweroutput drops to 89% of nominal value. The impact of 0.89 should be considered when analyzing the power output of the solar panel. coefficient.
The accumulation of dust on the surface of photovoltaic modules will affect the intensity of solar radiation radiated to the surface of the panel, and will also affect the output power of the solar panel. According to relevant literature reports, this factor will have an impact of 7% on the production of photovoltaic modules. When analyzing the power output of solar panels, an impact coefficient of 0.93 should be taken into account.
Due to the inhomogeneity of solar radiation, it is almost impossible for the output power of photovoltaic modules to reach the maximum power at the same time, so the output power of the photovoltaic generator is less than the sum of the nominal powers of each module.
In addition, there is an iunsuitability of photovoltaic modules and loss of panel connection, etc. The coefficient of these factors affecting the output power of solar panels is calculated to be 0.95.
The efficiency of the grid-connected photovoltaic plant after taking into account the installation angle factor is 0.88.
The real efficiency of electricity production is therefore O. 9 5 * 0.8 9 * 0.9 3*0.9 5 X*0.8 8=6 5.7% .
, The actual annual electricity production of the photovoltaic power generation system = Theoretical annual electricity production * Actual electricity production efficiency
=189.6 *0.9 5 * 0.8 9 *0.9 3*
0.9 5 * 0.8 8=189.6*6 5.7%=1.2456 million degrees< /p>
It varies from company to company and is for reference only
< p> Question 10: How to calculate the number of kilowatt hours of photovoltaic energy generated per day for a 1KW module with 6 hours of operationeffective sun, that's 6 kilowatt hours of electricity per day. The loss of independent systems is generally 30%. 6*0.7=4.2 kW/h. You must take into account the intensity of solar radiation. 6 hours of effective sunshine refers to the intensity of sunshine. The sun says effectiveThe number of hours refers to the intensity of the radiation.
Example:
If the unit of radiation is cal/cm2, then:
Maximum sunshine hours = radiation × 0.0116
0.0116 is the conversion factor to convert radiation (cal/cm2) to maximum sunshine hours:
Definition of maximum sunshine: 100 mW/cm2=0.1 W /cm2
1cal=4.1868 J=101868Ws 1h =3600s
Then: 1cal/cm2=4.1868Ws/cal(3600s/h×0.1W/cm2)=0 .0116hcm2/cal
For example: Suppose a certain place The annual horizontal radiation is 135 kcal/cm2 and the radiation on the square surface is 148.5 kcal/cm2,then the annual maximum sunshine hours are:
148500×0.0116=1722.6 h, the daily maximum sunshine hours are
p>
1722, 6÷365=4.7h