3,000 kcal. By researching the specific heat capacity of water, we know that 7 degree water requires 3,000 kcal of energy to reduce 80 degree water to 50 degree. Energy, called "power", is a measure of change in the space-time distribution of mass and is used to represent the ability of a physical system to do work. Modern physics has clarified the quantitative relationship between mass and energy.
How to produce water vapor at 80°C
The specific heat of water is of 4,200 J/kg·°C, and JO is work The unit of 1 joule = 1 watt second, that is, it takes 4,200 watt seconds of work to raise 1 kilogram d water by 1 degree Celsius, or 4.2 kW of electrical energy to heat for 1 second, 2.1KW to heat for 2 seconds...and so on
Let's assume in your question that 40KG of water are heated from 25°C to 80°C with a temperature rise of 55°C. = 40*55*4200=9240000 watts seconds If it's 6 minutes or 360 seconds Requires 9240000/360=25666.67 watts of power, or 25.67 kilowatts
Steam production method water at 80 degrees Celsius. :
1. Remove particle impurities from the rigid and smooth container to prevent a large number of condensation nuclei from appearing in the water vapor, and fill it with an appropriate amount of water;
2. Heat the water to 80 degrees Celsius to evaporate a large amount of water and expel all the air until it is full of water vapor, seal it and let it sit, wait for the steam water reaches saturation; /p>
3. Continuously compress the water vapor to near normal temperature. Water vapor cannot condense completely to a liquid state at the same time, it is supersaturated water vapor.