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Physics Hydroelectricity

By.Johns 2024-08-11 00:06:01 Share on facebook Share on Google Share on Instagram Share on Pinterest Share on Twitter Share on Tumblr Share on WhatsApp Share on Telegram Share on Reddit Visit our Instagram

Introduction The physical flow rate of hydropower is the volume that flows in one second. Suppose the sum of the reduction in gravitational potential energy and kinetic energy of flowing water in one second is multiplied by two yields and divided by one second.

Physics Hydroelectricity

Flow rate is the volume that flows in one second

Assume one second

Use the water that flows in one second

< p>

< p>The sum of the gravitational potential energy

the reduction of the kinetic energy

the sum

multiplied by< /p>

two

Efficiency

Divide by one second

That's the answer

{0.5* 1*1000*1000(3*3-2*2)+ 1000 *1000*10*10}*75%*80%=6.24*10^7w

The answer should be wrong

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