Find the power needed to pump 36O square meters of water to a height of 5 meters in 0.5 hour.

Introduction Find the power needed to pump 36O square meters of water to a height of 5 meters in 0.5 h. The mass of water in 36O cubic meters of water is m=pV=(1000kg/m^3)*360m^3=3.

Find the power needed to pump 36O square meters of water to a height of 5 meters in 0.5 hour.

The mass of water in 36O cubic meters of water is m=pV=(1000kg/m^3)*360m^3=3.6*10^5 kg

Pump 36O meters cubes of water for a height of 5 meters The minimum work to be done

=mgh=(3.5*10^5 kg)*(10N/kg)*5m=1.8*10^7 J

Power P=work /Time=(1.75*10^7 J)/0.5h=(1.8*10^7 J)/1800s=10000W=10kW

Considering mechanical efficiency issues, the required power should exceed 10 kW

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Is it cost effective to use a pump to pump water from the bottom to create overhead space to produce electricity?

Pumped storage power plant is a special type of hydroelectric plant that stores off-peak energy in the potential energy of water. It is used to produce electricity during peak electricity consumption hours. The remaining power from the electrical system is used to pump water to high places. excess energy is stored in the form of water. When the electrical systempower is insufficient, the water is released to produce electricity. A pumped storage power plant consists of an upper reservoir, a lower reservoir, a water conveyance channel, a factory building and a switching station. A pumped storage power plant is both a power plant and a user of electricity. It can convert excess electrical energy when used. the network load is low until peak power. In the era of high-value electric energy, pumped storage power plants are also suitable for frequency modulation and phase modulation, stabilizing the cycle and voltage of the power system, and are suitable for power backup. 'emergency. They can also improve the efficiency of the system’s thermal and nuclear power plants.

It is certainly not profitable simply based on the law ofenergy conversion and conservation. Pumping water with 100 kilowatt hours of electricity can only produce 60 or 70 kilowatt hours of electricity at most. in real life, pumping water can produce electricity. It's simple, the price of three kilowatt hours of electricity during off-peak hours is equal to the price of one kilowatt hour of electricity during peak hours. Water is pumped out at night. electricity is generated during the day. As long as the conversion rate exceeds 30%, there will be no loss. Similarly, you can also charge the battery and make ice at night to cool down during the day.

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