Generates 19.6 kWh of electricity. Use the formula to calculate the amount of electricity that a flow of water with a height of 5 meters and a flow rate of 0.5 cubic meters per second can generate: Electricity = flow second squared, the efficiency of turbine is generally about 0.8, electricity = 0.5 × 5 × 9.8 × 0.8 ≈ 19.6 kilowatt hours. A water flow of 0.5 cubic meters per second with a head of 5 meters can generate 19.6 kilowatt hours of electricity. Energy produced by hydropower is also affected by changes in water flow, maintenance and operation of turbines, and other factors. Hydropower also presents certain environmental and ecological problems, such as its impact on rivers, lakes and aquatic life.
How many cubic meters of water does a five-kilowatt hydroelectric generator need per hour?
0.27 kilowatt-hours of electricity. A cubic meter of water with a height600 meter water tower generates 0.27 kilowatt hours of electricity. Electricity is a natural phenomenon, which refers to the phenomenon caused by the movement of electrical charges. Lightning in nature is an electrical phenomenon. Electricity is a property of repulsive and attractive forces that develop between subatomic particles such as electrons and protons. It is one of the four fundamental interactions of nature. There are two phenomena of electron movement: atoms lacking electrons are said to be positively charged, and atoms with an excess of electrons are said to be negatively charged.
It also depends on the fall (height) of the water. Suppose the head is H (m), the flow rate is Q (m3/h), the power is P (kW) and the density of water is d (1000kg/ m3), the acceleration of gravity g = 10m/s2, taking into account the conversion efficiency μ, the relevant formula is: P = μdgHQ/3.6, if: μ=0.6, P=5kW, d= 1000kg/m3, H = 2m, Then Q = 3.6P/(μdgH) = 3.6x5/(0.6x1x10x2)= 1.5m3/h.
That is, when the generator has a height difference of 2 meters and a conversion efficiency of 0.6, the required water flow is about 1.5 meters cube per hour.