The flow rate must be 1000 m^3/s (the unit in the question is wrong)
The mass of water flowed per second: m=ρV=1000×1000kg=1 ×10^6kg
Reduced gravitational potential energy per second: mgh=1×10^6×10×80J,=8×10^8J
Electric energy obtained per second: 8 ×10^8 ×0.6J=4.8× 10^8J
Since it is electrical energy "per second", the value is the same as power
That is to say the power generated: P=4.8 ×10^8W=4.8×10^5kW< /p>