Suppose the reference flow rate of the hydro-generator unit is Q, then P = 300,000 kW = 9.81 QHe in the formula H = 100 m (water height); e is the efficiency if the unit operates below water level; design working conditions, the efficiency of this unit can reach 92%; therefore Q=300000/9.81/100/0.92=332.4m?/s, therefore water consumption per hour: 332.4*3600=1196649m?
#tag:hydraulic turbine generator#quote flow# Efficiency#水头#Water consumption
The conversion rate of hydroelectric power has two aspects.
The first consists of purely calculating the efficiency of the conversion of the potential energy of water into electrical energy, that is to say of the conversion of the potential energy of water into the kinetic energy of water. loss of water channel here, and the efficiency is about 95%. It is then converted into the kinetic energy of the turbine, where the efficiency of the turbine is approximately 90%. She is enthen converted into kinetic energy of the generator, where there is virtually no loss. It is then converted into electrical energy. where it is around 95%. Taken together at the outlet of the hydroelectric plant, the efficiency is generally 80%. Then, converted to real energy efficient for end users, there is a huge gap. A small, isolated power grid can be as low as less than 50%, while a large power grid can be as low as 85%.
Another concept of efficiency is the efficiency of total installed capacity. Generally, the rated capacity is the maximum water height and flow rate, but in fact, due to the influence of dry periods, peak load regulation of the power grid, regular maintenance, etc. , the average annual electricity production is typically about 40% of that of water. design value.