Mass per unit time: m=2*1000=2000kg
v1=3, v2=1
h-1.6
p =mgh+( 0.5 mv1?-0.5mv2?)*0.75*0.8/1 second
=[2000*10*1.6+0.5*2000*(9 -1)]*0.75*0.8
=[32000+8000]*0.6
=24000w
=24kw
Your 20% should be the overall efficiency of the hydraulic generator! Are you looking for traffic?
According to P=9.81QHη flow rate Q=200÷9.81÷20÷20%=5.1m3/s
PS: The question of an overall efficiency of 20 % is not impossible. Now, the overall efficiency of large-scale hydroelectric turbine units is generally above 90%. Small hydroelectric units offering better conditions generally have an efficiency of 60 to 70%. As for smaller hydroelectric units, 20% or even less is possible. what we use here? It is used little by little. For example, in some places, a bamboo tube is used to connect water, and there are bamboo joints in the middle. The pipes are twisted and twisted. can efficiency be?