How many degrees of electricity does it take to heat 1 cubic meter of water to 100 degrees Celsius?

Introduction How many degrees of electricity are needed to heat 1 cubic meter of water to 100 degrees Celsius? If water is heated from 20 degrees Celsius to 100 degrees Celsius, 97.778 degrees of electricity are required to heat 1 cubic meter of water to 100 degrees C

How many degrees of electricity does it take to heat 1 cubic meter of water to 100 degrees Celsius?

If heated from 20℃ to 100℃, heating 1 cubic meter of water to 100℃ requires 97.778 degrees of electricity.

The calculation method is as follows:

The specific heat of water is 4.18 kilojoules/(kilograms degrees Celsius), 1 cubic meter of water is equivalent to 1000 kilograms, assuming efficiency is 95. %

W×95%=1000×4.18×(100-20)

W=1000×4 .18×(100-20)÷0.95=352000 kilojoules

1 degree Electricity = 3600 kilojoules

352000÷3600=97.778 (kWh)

< p>Detailed information:

95% of the heat generated by the electric heating tube is absorbed by the water. According to this equivalence relationship, the heat required to heat 1 cubic meter of water from 20 degrees Celsius to 100 degrees Celsius is equal to 95% of the heat generated by the electric heating tube. heat emitted from the electric heating tube for careduce electricity consumption.

When there is a temperature difference between the system and the outside world, we say that there is a thermal interaction between the system and the outside world. The result of the action is that energy is transferred from the high temperature object to the low temperature object. The energy transferred at this time is called heat.

Heat and work are two different forms of energy transfer that occur during changes in the state of the system. These are measurements of different forms of energy transfer. They are both linked to the intermediate state change process and are therefore not functions. of the state of the system.

Calorie unit: In nutrition, “kilocalories” is used as a unit of calories. 1 kcal is the quantity of heat necessary to raise 1 liter of water by 1 degree from 15°C.

After a certain process, the temperature changes to △t and absogenerates (or releases) heat. Q represents heat (J),

Q=c·m·Δt

Q absorb=c·m·(t-t?)

Q release = c ·m·(t?-t)

(t? is the initial temperature; t is the final temperature)

Where C is the specific heat (capacity) linked to this process .

The units of heat are the same as those of work and energy. The unit of heat in the International System of Units is the Joule (abbreviated Joule, abbreviated J) (erected in memory of the scientist Joule). Historically, the unit of heat has been defined as the calorie (abbreviated cal), which is only used as an auxiliary energy unit, 1 calorie = 4.184 joules.

Note: 1 kcal = 1000 calories = 1000 calories = 4184 joules = 4.184 kilojoules

The heat absorbed by a certain area over a certain period of time is related to the heat released and stored. maintain a balanced relationship.

△T=(t?-t?)

Baidu-Heat Encyclopedia

How many joules aret consumed to raise 1 ton of pure water from 0 degrees Celsius to 100 degrees Celsius, and how many kilowatt hours of electricity are consumed?

Sanyou Electric is your answer: 60 KW can raise the temperature of a ton of water to 100 degrees in an hour. *60KW is the electricity required. 1 KW operating at full load in one hour is equal to 1 kilowatt hour. electricity.

It is recommended to understand?

Sanyou - Electromagnetic boiler - Heat conversion rate reaches 98%. It adopts separate heating of water and electricity, which is safe and without hidden dangers. It does not produce tartar. Compared with gas and electric heating equipment, it saves 20-30% energy. It can drive radiators and underfloor heating pipes, fan coils and other heat dissipations, can be used in all projects. require heating (including supply en hot water for baths, high temperature in hammams)?

You get what you pay for, here is a comparison

< p>Comparison between an electromagnetic heating oven and resistance heating furnace

Electromagnetic heating furnace:

1. Electromagnetic induction heating, true separation of water and electricity, insulation of circuits and waterways.

2. Low-voltage soft start reduces damage caused by power surges, avoids equipment damage due to voltage fluctuations, and ensures safety.

3. The variable frequency power output part can automatically adjust the current according to voltage fluctuations to ensure constant power and will not cause damage due to insufficient electrical load due to increase in voltage and increase in current.

Resistance heating oven:

1. TheResistance heating, whether the resistance material is inside or outside, is carried out through the heat-conducting medium. This is not a true separation of water and water. electricity. There is a hidden danger of leakage due to corrosion or breakdown.

2. The relay directly powers the resistance rod, and the impact current is large, which is prone to overcurrent impact and voltage fluctuations, and may also damage other electrical appliances.

Structural design

Electromagnetic heating furnace: the water circuit and the circuit of the whole machine are separated, reasonable structure, high safety

Resistance heating furnace: water and electricity is not separated in the whole machine, great safety risk

Energy saving

Electromagnetic heating furnace:

High frequency electromagnetic induction heatingacts directly on the water The bladder by electromagnetic induction, causing the bladder itself to heat up, reduces the conduction process through the medium, with less heat loss and high thermal efficiency. It heats immediately when added, without the need for a heat storage container. be as high as 98% or more, saving more than 30% energy compared to the resistive type.

Resistance heating furnace:

1. Resistive heating conducts heat to the water tank through the heat-conducting medium, resulting in significant heat loss

2. Local heating is easy to produce Scale affects heat conduction

3. Some materials are seriously attenuated, resulting in low thermal efficiency

> Service life

Electromagnetic Heating oven: industrial grade electromagnetic wire, resistant to highes temperatures, used for more than 15 years

Resistance heating furnace: resistance wire is easy to age, short life, generally 3-5 years

Quiet

Electromagnetic heating furnace: the frequency of heating power is 20,000 Hz, which exceeds the normal hearing of the human body. It not only improves thermal efficiency, but is also quiet and environmentally friendly.

Resistance heating furnace: There is a "buzzing" industrial frequency noise when the industrial frequency power supply is operating. Resistance water heating, when the surface water temperature is high, bubbles produce the sound of boiling water. .

Maintenance

Electromagnetic heating furnace: electromagnetic induction heating. When operating, the heating core component is a fixed magnetic field after passing through it, and theThe structure of water is magnetized. , making the system maintenance free.

Resistance heating oven: The resistance wire is generally replaced every 3 to 5 years, and as it produces scale, it must be descaled regularly.

The above content is for reference only. If you have any questions, please communicate and correct them in time.

How many kilowatt hours of electricity does it take to raise a ton of water 100 degrees?

1 ton of water = 1 × 1,000 kilograms d 'water

p>

The specific heat of water C is 4.2×1000 J/(kg?℃)

Q=cm△t=4 .2×1000 J/(kg?℃)×1×1000kg× (100-0)℃=4.2×100000000 Joules

If the energy loss is not included, the electrical energy = internal energy absorbed by the water, or 4.2 × 100000000 joules

1 kilowatt hour of electricity = 3.6 × 1,000,000 joules, this therefore represents approximately 116.67 kilowatt hours of electricity

Note: the calculations above take into accountWe take into account the fact that the water did not freeze at 0 degrees and did not turn into water vapor at 100 degrees. Because the state of the water changes, the specific heat also changes.

< p>The specific heat of water is 4.2×10^3 J/(kg×°C), this which means that the mass of water is 4.2×10^3 J/(kg×°C). 1 kg, and the temperature increases (or decreases) by 1°C, the heat absorbed (or released) is 4.2×10^ 3 joules. 1 degree=1000W*3600S/H=36*10^5 Joules.

According to cmΔt=Q:

10^3*100* 4.2×10^3=42*10^7 Joules;

42*10 ^7 / (36*10^5) = 116.67 kWh

Because the utilization rate of the electric cathode is only about 80%,

So , total electricity consumption = 116.67/(80%)=145.83 kWh.

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