It also depends on the height of the water (height). Suppose the height is H (m), the flow rate is Q (m3/h), the power is P (kW), the density of the water is d. (1000kg/m3), and the gravitational acceleration g =10m/s2, taking into account the conversion efficiency μ, there is a relationship: P = μdgHQ/3.6 If: μ=0.6, P=5kW , d=1000kg/m3. , H = 2m, then Q = 3.6 P/(μdgH) = 3.6x5/(0.6x1x10x2)= 1.5m3/h.
That is, when the generator has a height difference of 2 meters and a conversion efficiency of 0.6, the required water flow is about 1.5 meters cube per hour.
The air pressure is 0.8 MPa, which is equivalent to a water depth of 80 meters. Generally, it can be estimated that 6.5 cubic meters of water can generate one kilowatt hour of electricity. cubic meters of water are consumed, 6.15 kilowatt hours of electricity can be generated (take 6 kilowatt hours), or 2KW can be sent for 3 hours. The principle is that the firstatmospheric pressure remains constant. In fact, the electricity you use for pumping must be much higher than the electricity produced by the generator, can you believe it? .