Energy production by water flow is the conversion of the gravitational potential energy of water into the kinetic energy of water, then into electrical energy. When calculating the power of a generator, it is necessary to first calculate the power of the gravitational work of water and then calculate. the output electrical power of the generator based on the power generation efficiency. When calculating the ratio of the turns of the step-up transformer and the coils of the step-down transformer, you can first find the ratio of currents passing through the primary and secondary coils. The current in the primary coil of the step-up transformer can pass through the power plant. The output power and output voltage are calculated, that is, I1 = Pout/U1 is the current in the transmission line; calculated from the power lost in the transmission line, i.e. it should be notedr here that I0 passes through the step-up transformer. The output current is the input current through the step-down transformer.
The output current of the step-down transformer can be calculated from the user power and the output voltage. The user power is equal to the generator output power and the power difference of the transmission line. transmission line = P use/U use.
(1) Using the mechanical energy of water to produce electricity, the water flow per second is 4 m3, the height of the water is 5 m and the water drives the generator The power of the wheel is:
5m×50%×4m^3/s=9.8×10^4W(2 )
Step-up transformer, output P =I1U1
I1=P has/U1=9.8× 10^4W÷350V=280A The electrical power lost on the transmission line is
P loss = P × 5% = 9.8 × 10^4W × 5% = 4900WI2^2R = P loss I2^2 × 4Ω = 4900WI2=35A step-down transformer for P=P has-Ploss=9.8×10^4W-4900W=93100W
< p> I3=For P/U3=93100W÷220V=9310/22AThe ratio between the turns of the primary and secondary of the step-up transformer is I2: I1=35A: 280A=1:8. The turns ratio of the primary and secondary coils of the step-down transformer is I3: I2=9310/22A: 35A=133:11
A 20 kilowatt hydroelectric generator requires a water head and flow rate<. /h3>
~~~~~~~~~~~~P=9.8gQH
P is the output power, the unit is kilowatts;
9.8, which is the acceleration of gravity;
g is the efficiency, which can be simply considered to be between 0.8 and 0.9 for general power plants;< /p>
Q is the flow rate, unit: cubic meter/second;
H is the water height, also called head drop,
P=9, 8*0.85*0.4*100=27.2KW.
It is recommended to purchase a hydroelectric generator with a production power of 30KW. Electricity production capacityis 27 kilowatt hours per hour~~~~~~~~~~
The above formula is correct, but the answer is too different
P=9.8GQH=9.8 *0.8*0.6*100=470KW The water height of 100 meters is equipped with 27.2kw. I don't know how to calculate it, even if the flow rate is 0.4 it won't be that small. Regarding efficiency, generally small unit generators take 0.8, hydraulic turbines also take 0.9, and complete ones take 0.8. an impact type, the yield is 2 points lower, takes 0.8, and the mixed flow takes 0.82. The mine is a positive solution with an impact of 400KW or 500KW. This site chooses 500. 500 degrees per hour
A 200 kW hydroelectric generator requires water pressure
I don't know how to answer this question. A 20 kW unit can be combined with many data sets. it's simple: in H= 20m, with a flow rate of 0.14~0.15m3/s, you can generate 20KW. At H=7m, with a flow rate Q=0.5m3/s, you can also generate 20KW. your water loads and flow rates? The preliminary calculation formula is: P(kw)=H*Q*9.81*0.7
A 200 kW hydroelectric generator requires 10-15 mV water pressure.
A hydroelectric generator is a machine that converts the kinetic energy of water flow into electrical energy. When designing and operating a hydroelectric generator, two major parameters, water height (difference in water level) and flow rate, are mainly considered. considered. Water height refers to the height to which the water falls, which determines the kinetic energy conversion capacity of the water to the turbine; flow rate refers to the amount of water passing through the turbine per unit time, which determines the power generated by the turbine; the generator. Therefore, for a 200 kW hydroelectric generator, the design head and flow rate must bedetermined, and the water pressure can be calculated based on the selected head and flow rate.