How big can a flush generator support a pipe with a height of 50 meters and a diameter of 110 mm?

Introduction A pipe with a height of 50 meters and a diameter of 110 mm can carry a flush generator of approximately 200 to 300 watts. 1. Head difference is one of the important factors in hydropower generation. Water height with a fall of 50 meters

How big can a flush generator support a pipe with a height of 50 meters and a diameter of 110 mm?

Approximately 200-300 watts.

1. Head drop is one of the important factors in hydropower generation. The water height with a head of 50 meters can generate significant potential energy to provide energy for hydroelectric power generation.

2. The diameter of the pipe affects the speed and flow of water. A water pipe with a diameter of 110mm can ensure a certain speed and flow of water, thereby providing sufficient power for hydroelectric power generation.

3. Water flow speed is one of the key factors in hydropower production. The faster the water flows, the more energy is generated.

Efficiency and selection of hydraulic generator sets

Selection of microturbines:

Microturbines are mainly divided into two types: impact type and counter type -attack:

p>

Impact types include the type tobucket, oblique impact type and double click type, which are suitable for high water heights and small flow rates. For example, bucket turbines are suitable for water heights of 100 to 1,000 meters.

Impact turbines include axial flow type and mixed flow type, which are suitable for low heads and large flow rates. For example, Francis turbines are suitable for water heads of 20 to 200 meters, tubular turbines are suitable for water heads of 2 to 16 meters, and axial flow turbines are suitable for water heads of 2 to 30 meters.

Depending on the hydraulic parameters you provide, an impact type turbine can be selected. Among them, tubular flow turbine or axial flow turbine is the first choice.

Selection of micro-hydroelectric generator sets:

Micro-hydroelectric generator sets include asynchronous generators, synchronous generators and gpermanent magnet generators, which are divided into single-phase and three-phase generators.

Asynchronous generators are mostly generators modified from electric motors and capacitors. It has the disadvantages of unstable voltage, inconvenient operation, and unstable voltage hindering the use of household appliances. It is practically not used at present.

Ordinary synchronous generators use a rectifier to rectify alternating current and supply it to the magnetic field of the generator stator. The effect is better than that of asynchronous generators. However, most generators have slip ring carbon brushes and are not. closed structures subject to humidity. It is necessary to frequently replace the carbon brushes and maintain the slip rings. These tasks require certain professional and technical knowledge to beaccomplished. Users from backward areas should not use it. After use, this will cause major maintenance work for users. The selection of these micro-hydropower generation units should be carefully selected based on the area of ​​use.

The permanent magnet generator is currently an ideal unit. It has no wear components such as rectifier slip rings and carbon brushes. It has a fully enclosed structure and is dustproof and waterproof. With normal use, care and refueling, it requires virtually no maintenance. It has high reliability and is especially suitable for users in backward areas.

Single-phase generators only need two wires to transmit power, and the power transmission cost is low, but they are only suitable for small units (10KW or less ).

Three-phase generators have high efficiency and require four wires to transmit power. For units over 10 kW, they typically use three-phase, four-wire power transmission.

We see that you must choose a single-phase permanent magnet generator.

Usually, manufacturers provide good matching equipment.

~~~~~~~~~~~~P=9.8gQH

P is the output power in kilowatts;

9.8 , this is gravity, acceleration;

g is the efficiency, which can be simply taken as 0.8~0.9 for general power plants;

Q is flow rate, unit: cubic meter/second; p>

H is the water height, also called gap,

P=9.8*0.85*0.4*100=27.2KW.

It is recommended to purchase a hydroelectric generator with a production power of 30KW. Electricity production is 27 kilowatt hours per hour~~~~~~~~~~

The above formula is correct, buts the answer is too different

P=9.8GQH= 9.8*0.8*0.6*100=470KW. I don't know how to calculate 27.2kw per 100 meters of water height. Even a flow rate of 0.4 is not that small in terms of efficiency, small unit generators usually take 0.8, and turbines. also take 0.9. Full Take 0.8. If it is an impact type, the return is 2 points lower, so take 0.8. For mixed flow, take 0.82. For the positive solution, I choose impact 400KW or 500KW. 500 for this station. 500 degrees in an hour

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