We need to calculate the normal operating current of a 3KW three-phase motor at a voltage of 380V.
First of all, we need to understand the relationship between power, voltage and the current.
The relationship between power (P), voltage (V) and current (I) can be expressed by the following mathematical formula:
P = V × I
p>< p>This formula tells us that the motor power is the product of voltage and current.Therefore, current (I) can be expressed as:
I = P/V
This formula tells us that current is power divided by tension.
Substitute P=3KW=3000W into the above formula and voltage V=380V to get the answer.
The result of the calculation is: the motor current is 8.42 A.
Thus, the normal operating current of a three-phase motor of 3 kW at a voltage of 380 V is 8.42 A.
Suppose that in one minute, the mass of water M water = 1000*60 = 60000kg, donc the work done by the water W = Mgh = 60000*9.8*50 = 29400000, then the power P = W/t =29400000/60=490000w If you want to install a generator, assuming H net = 48 m, then the output N = KQH net = 7.5*60*48 = 21600kw.