Heating a ton of water to 55 degrees requires 124 kilowatt hours of electricity. The calculation method is:\x0d\The specific heat of water is 4.2 × 10^3 J/(kg × ℃), which means that the mass of water is 1 kilogram and the temperature increases (or decreases) by 1. ℃, the heat absorbed (or released) is 4.2×10^3 joules. 1 degree=1000W*3600S/H=36*10^5 Joules. \x0d\According to cmΔt=Q:\x0d\10^3*55* 4.2×10^3=23.1*10^7 Joules;\x0d\23.1*10^7 / (36*10^ 5) = 64.2 degrees Electricity\x0d\Since the maximum utilization rate of electric energy is only 52%,\x0d\therefore, the total electricity consumption = 64.2/( 52%) = 123.5 kWh. \x0d\\x0d\Specific heat capacity, represented by the symbol C, is also called specific heat capacity, called specific heat (specific heat). This is the heat capacity of a unit mass of material, i.e. absorption. of a unit of mass of an object when it changes temperatureunitary nature. The ratio of the heat absorbed by a substance of a certain mass when the temperature increases to the product of the mass of the substance and the increasing temperature is called the specific heat capacity (specific heat) of the substance, represented by the symbol c .
How many kilowatt hours of electricity does it take to lower a kilogram of water by one degree?
It takes 0.0011667 kilowatt hours of electricity to raise the temperature of a kilogram of water (normal temperature) by one degree.
Analysis
The specific heat capacity of water
According to the energy calculation formula, the energy required for water to increase its temperature will be
p>be
< p>Substituting the above equation, we getEven if the temperature of water of one kilogram of water (normal temperature) increases by one degree, this requires 0.0011667 kilowatt hours of water. electricity.
How much electricityty is required to raise the temperature of a ton of water by one degree?
It takes 0.0011667 kilowatt hours of electricity to lower the temperature. temperature of a kilogram of water (normal temperature) by one degree.
It takes 0.0011667 kilowatt hours of electricity to raise the temperature of one kilogram of water (normal temperature) by one degree. Specific heat capacity of water According to the energy calculation formula, the energy required to increase the water temperature will be substituted into the above formula, that is, even if the temperature of water from one kilogram of water (normal temperature) increases by one. degree, it requires 0.0011667 kilowatt hours of electricity.
Calculate the specific heat capacity of water. What is the volume of one kilogram of water? Use the formula for volume and specific heat capacity to calculate it. 1 kilowatt hour of electricity = 1 kWh = 3,600,000 joules. Just convert itr in thermal energy (unit of joules).
11.63 kWh. The heat required to raise a ton of water one degree is 4.1868×10(7) joules. The energy of one degree of electricity is 1 kilowatt hour, or 3599712 joules when converted to joules. If electrical energy is converted into thermal energy without any loss, the amount of electricity required is 11.63 kWh.