How does one of the two + of a hydroelectric generator transform into -

Introduction How to convert one of the two + wires of a hydroelectric generator to - If you measure it with an electric pen under load, both wires are charged. From what you've said it sounds like it's single phase causing the charger. Burnout.

How does one of the two + of a hydroelectric generator transform into -

If you use an electric pen to measure the voltage on both wires with a load, it must be single phase from what you said

The reason the charger burns out is because the voltage is too high. It is recommended to use a multimeter to measure the voltage or check the voltage level of the connected device to make sure it is 220V and then adjust the output voltage. If the output is 380V, a transformer is required.

How many cubic meters of water does a five-kilowatt hydroelectric generator need per hour?

~~~~~~~~~~~~P =9.8gQH

P is the output power, the unit is kilowatt;

9.8, which is the acceleration of gravity;

g is the efficiency, which can be simply taken as 0.8. ~0.9 for general power plants;

Q is flow rate, unit: cubic meter/second;

H is water height, also called head drop,

P=9.8*0.85*0.4*100=27.2KW.

It is recommended to purchase a hydroelectric generator with a production power of 30KW. Electricity production is 27 kilowatt hours per hour~~~~~~~~~~

The above formula is correct, but the answer is too different

P =9.8GQH= 9.8*0.8*0.6*100=470KW. I don't know how to calculate 27.2kw per 100 meters of water height. Even a flow rate of 0.4 is not that small in terms of efficiency, small unit generators usually take 0.8, and turbines. also take 0.9. Full Take 0.8. If it is an impact type, the return is 2 points lower, so take 0.8. For mixed flow, take 0.82. For the positive solution, I choose impact 400KW or 500KW. 500 for this station. 500 degrees per hour

Simple generator principle

It also depends on the fall (head) of the water. Suppose the head is H (m) and the flow rate is Q. (m3/h), the poweris P (kW), the density of water is d (1000kg/m3), the acceleration of gravity g =10m/s2, considering the conversion efficiency μ, there is a relationship: P = μdgHQ/3 .6, if: μ=0.6, P=5kW, d=1000kg/m3, H = 2m, then Q = 3.6P/(μdgH) = 3.6x5/(0.6x1x10x2)= 1.5m3/ h.

That is, when the generator has a height difference of 2 meters and a conversion efficiency of 0.6, the required water flow is about 1.5 meters cube per hour.

There is a river with a flow of 4 m 3 /s and a fall of 5 m. It is now used to produce electricity. The efficiency of electricity generation is 50%. The generator output voltage is 350V. Power Transmission

Generators are generally composed of stators, rotors, end covers, bearings and other components. The stator consists of the stator core, wire windings, machine base and other structural parts that fixnt these parts. The rotor consists of a rotor core winding (or magnetic pole, magnetic yoke), guard ring and center ring, slip rings, fans and rotating shafts and others components.

The stator and rotor of the generator are connected and assembled by the bearings and end covers, so that the rotor can rotate in the stator and carry out the cutting movement of the magnetic lines of force, thus generating an induced effect. electric potential, which is discharged through the terminals and connected to the circuit, an electric current is generated.

A general generator first converts the energy contained in various primary energy sources into mechanical energy through the main engine, then converts it into electrical energy through the generator, and then sends it to various places of energy consumption via the power supply. transport and distribution networks.

Type

Due to differents forms of primary energy, different generators can be made.

1. Hydraulic generators can be made using hydraulic resources and hydraulic turbines of different capacities and speeds can be made using the position difference. As for the downward flow, the energy of the water flow drives the turbine to produce electricity. However, the disadvantage is that if the position difference is too small and the flow speed is not fast enough, stable power supply cannot be provided.

At present, there is a way to generate electricity using ocean currents, but the generator is often damaged due to too strong ocean currents or excessive pressure under the surface of the sea.

2. Using coal, oil and other resources, combined with boilers and steam turbines, turbogeneratorsators can be manufactured. Most of these generators are high speed motors (3000 rpm).

3. Additionally, there are different types of generators that use wind energy, atomic energy, geothermal energy, tides and other energies.

?

Detailed information:

Development History

When electromagnetic induction was discovered, the method of generating alternating current was known. The first finished products were developed by Michael Faraday and Polit Pixie.

In 1866, Werner von Siemens proposed the operating principle of the generator, and a Siemens engineer produced the first alternator.

In 1882, British electrician James Gordon built a large two-phase alternator. Lord Kelvin and Sebastian Ferranti developed the first alternators with frequencies between 100 Hz and 300 Hz.

In 1891, Nikola Tesla patented a “high frequency” alternator (15,000 Hz).

After 1891, polyphase alternators were used to provide power. The alternating current frequency of later alternators was generally designed between 16 Hz and 100 Hz and was used with arc lamps, incandescent lamps or electric motors.

When the magnetic field around a conductor changes, an induced current is generated in the conductor. Typically, the rotating magnet is called a rotor, and the stationary group of conductors wound in a coil around an iron core, called a stator, produces an electric current when it passes through a magnetic field.

Step-up transformerThe transformation ratio of the original and secondary coils is 1:8; the transformation ratio of the primary and secondary coils of the step-down transformer is 133:11

< p>

Analysis of test questions: Draw the transmission line as shown in the figure

Assume the work power The maximum output power of the generator is the power d input P1. of the step-up transformer.

According to the question

on the transmission line, the allowable electrical energy consumption is,

From, we can get

p>

The voltage at both ends of the secondary coil of the step-up transformer is

The turns ratio of the primary and secondary windings of the step-up transformer is therefore

p>The voltage across the primary coil of the step-down transformer is,

So, the transformation ratio of the primary and secondary coils of the step-down transformer is

Comments: The The primary and secondary coils of the transformer depressor are. The turns ratio is equal to the voltage ratio of the primary and secondary coils, to the power lost on the litransmission problem and lost voltage. Mastering the power relationship and the tension relationship is key. to resolve this problem.

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