There is probably something wrong with the calculations on the first floor.
Q=cmΔt=4.2*1000*4000*50=840000000 joules That is to say, it takes a total of 840000000 joules of energy to heat 4 tonnes of water at 50 degrees.
If it is necessary to generate 223.33 degrees of electrical energy in 1 hour, then at least 233.33 kilowatts of heating pipes are required to provide it.
If it takes two hours, 116.67 KW is enough
As for whether the voltage is 380 or 220, it has nothing to do with the power, only the current size
How many degrees can a 4000 watt heating rod heat water in one hour? I want to heat a ton of water to around 20 degrees?
Water decomposes into hydrogen and oxygen when it encounters the high temperature of a flame. Because water is composed of the elements hydrogen and oxygen, hydrogen is flammable and oxygen supports combustion. . But ifyou have a lot of water, you have to use a lot of fire. . This problem is a bit like a volcanic eruption. . Earth's internal forces cause volcanic eruptions, but when volcanoes are dormant, they often turn into a pool of water.
How long does it take for water to heat up from 15°C to 70°C? Suppose the water heater power is 2000W and the water is heated from 15℃ to about 55℃. How much energy is consumed? Thanks
1 kilowatt hour of electricity is 3.6 MJ, 4 kw is 14.4 mj per hour
If each kg of water is heated from 0 to 20 degrees , 4.18x10^3x1x20=0.0836 md
One meal equals 1000*0.0836=83.6 md
83.6/14.4 equals approximately 6 hours
This is an ideal state in which all the heat is absorbed by the water, and the heat from the water has not dissipated
In fact, this may take more than 6 hours (this mainly depends on whether your water tank1 ton is well insulated)
Specific heat capacity: at a certain temperature, unit of mass The heat absorbed by a substance for each increase in degree Celsius
The specific heat capacity of the water is: 4.2 kJ/(kg?℃), converted to metric units: 4.2×10^3J/(kg?℃)
p>Then: 80 liters of water rise from 15 degrees Celsius to 55 degrees Celsius, the actual increase is 40 degrees Celsius,
Work required = 4.2×10^3×80×40=1.344×10^7J
To convert kilowatt hours to metric units, time must be converted to seconds
This 1 kilowatt hour = 1000 W? h = 1000 W × 3600 S = 3.6 × 10^6 W? s
Power consumption = (1.344 × 10^7 J) ÷ (3.6 × 10^6 W? s) = 3.73 < /p>
That's 3.73 kilowatt hours of electricity
3.73÷2=1.87 (hour) corresponds to approximately 1 hour and 52 minutes.
This is only a theoretical calculation, the real situation is much more complicated...
The electricity consumption ofan electric water heater mainly depends on your water consumption. Hot water consumption is directly proportional to your electricity consumption. Saving hot water means saving electricity.