Suppose a hydroelectric power reservoir has a flow rate of 9,000 cubic meters/s, a height of 40 m, a

The work done by water per second W=mgH=ρgVH=1000*10*9000*40=

Converted into electrical energy in a day=75%W*24*60*60 = unit This is joules then converted to kilowatt hours

Please do the calculation yourself

Water consumption per second = N/H/K (cubic meters)< /p>

N — —Hydropower plant power (KW)

H——Hydropower plant nominal height (meter)

K——Output coefficient: 8.0~8.5 related to the efficiency of the unit

< p>For example: A hydroelectric power station has a nominal water depth H = 100 meters. When power generation is 1000 kW, water consumption per second = 1000/100/8.2 = 1.22 (cubic meters), water consumption per hour = 4390. cubic meters , and the daily water consumption is 105,000 cubic meters of rice.