2Al+6H20===2Al(OH)3+3H2 (heating).
From a query on Baidu Education, we learned that the topic is: Chemical equation of the reaction between aluminum and water. Answer: 2Al+6H20===2Al(OH)3+3H2 (heating). This reaction is also very weak when heated and can be ignored.
Because aluminum has a variety of excellent properties, aluminum has an extremely wide range of uses. According to the reducibility of aluminum, it can be inferred that aluminum can react with water, but experiments have shown that aluminum has. almost no reaction with boiling water, but aluminum present. It can react significantly with water vapor under heating conditions, but as soon as the reaction begins, it forms a dense oxide film with the oxygen present in the water to prevent the reaction from continuing.
The ionic equation for the reaction between aluminum ionsum, metaaluminate and water, what's the step by step process in the equation?
It is an aluminum-air battery. The power supply for the navigation lights is as follows: positive electrode: 3O2+12 e- +6H2O =12 OH- negative electrode: 4 Al-12 e-=4. Al3+ Al3+ + in the subsequent reaction 3OH-= Al (OH) 3 ↓ Because Al is the negative electrode, it loses electrons and produces Al3+O2 in a neutral environment. It is an oxidant and reacts at the positive electrode to obtain electrons and. becomes OH-
Aluminum-air fuel cell, when sodium chloride or sodium hydroxide is the electrolyte, the overall reaction equation is the reaction process and the reason for the products reaction of aluminum, oxygen and water
The joint reaction of aluminum ions, metaaluminate and water is essentially a double hydrolysis
( 1) Al(3+) + 3H2O = reversible = Al(OH)3 + 3H(+)
(2) AlO2(-) +2 H2O = Reversible = Al(OH)3+OH(-)
(1) + (2) x3 eliminates approximately 3 H2O (3H( +)+3OH(-)=3H2O)
< p> Obtained: Al(3+) + 3AlO2(-) + 6H2O == 4Al(OH)3↓
The first step is the reaction of aluminum ions and metaaluminate hydroxide and water: Al3+ + 4OH- (excess) = AlO2- + 2H2O
The second step is to generate aluminum ions and water from metaaluminate ions and hydrogen: AlO2- + 4H+ (excess) = Al3+ + 2H2O
It is a mutual conversion reaction by addition of excess acid and alkali. Of course, it cannot be added without the formation of Al(OH. )3.
Hope this can help you, 8, the ionic equation of the reaction between aluminum ions, metaaluminate and water, find the process step by step from the equation,
I remember that the first step is the reaction between aluminum ions and hydroxide to form metaaluminate and water, the second step is metaaluminate and hydrogen ions generate aluminum ions and water, and addition cannot produce the equation Al3++3AlO2-+6H20=4Al(OH)3 (arrow),
(1) Aluminum-air fuel cell, sodium chloride is the electrolyte
(-)4AI+12OH- - 12e- = 4AI(OH)3
( +)3O2+ 6H2O + 12e- = 12OH-
Total: 4AI+3O2+ 6H2O = 4AI(OH)3
(2) Aluminum-air fuel cell with sodium hydroxide as electrolyte
(-)4AI+16OH- - 12e- = 4AIO2^- + 8H2O
(+)3O2+ 6H2O + 12e- = 12OH-
Total : 4AI+3O2+ 4OH- = 4AIO2^- + 2H2O