The total electrical power required in a day: 2*60*8+20*24=1440 w*h
Assuming the day (the duration for which the solar battery can provide electricity 'energy) is 8 hours, then the solar battery needs the minimum charging power supplied (regardless of charging efficiency and inverter conversion) is 1440/8 = 180 W (which is the average power, the instantaneous maximum power is 140 W and the minimum power is 20 W). assuming the overall efficiency is 50% (a little lower), the power of the solar cell is at least 360W (maximum instantaneous power is 280W, minimum power is 40W assuming that This is a 12 V battery, the average current). is 360/12 = 30A. I just looked at solar cells on Taobao.
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From the information above, it appears that it is not cost effective to use solar cells for your system because you are not in an area that lacks electricity ( otherwise there would be no aquarium~), if you use it this way, even if the lifespan of the solar panel is not taken into account, it is not cost-effective.
It is recommended not to adopt this solution, as it is too expensive to implement and cannot be maintenance-free. If two elements (dry feedtor and solar energy) can perform the same function, you must choose that one. with a simple structure. In this way, the system stability is high!
I don't think it's feasible
First of all: the function of an aerator is to increase oxygen, and in the case of sufficient sunlight , water can be cultivated through the action of light. Experimental studies have shown that in water, a very small part of the oxygen is dissolved by water mixing, and most of it is produced by the light interaction of phytoplankton. However, when it is necessary to increase oxygen on cloudy days or cloudy days. at night there is no sun, so it makes no sense.
Second: The radiation power of solar energy is very limited. It appears that on the cloud layer the total radiation energy per square meter is on the perpendicular plane. the rays of the sun surround thes 1300 watts, and it is difficult to convert everything into electrical energy
So it is very difficult. Complete your hypothesis