Tramway departure and arrival stations

40 minutes

Explanation: When leaving from station B, a car has just left station A, and there are 4 cars on the road at this time (2 cars between station A and station B, 2 cars at station A and vehicles at station B), we encountered 10 vehicles on the road, and when we arrived at station A, another one left, which means that it There were 12 vehicles in total when we first left. there were 4 vehicles total on the road, so there were 4 vehicles since he left, so we left. When we arrived, there were a total of 12 cars, and the time was the interval between 8 cars. The interval between a car was. 5 minutes, and the interval between 8 cars was 40 minutes!

Route problem

11. How much does the rest cost?

A: (1-2/5)*(1-2/3) *( 1-2/5)a

B: (1- 2/3)*(1-2/5)*(1-2/3)b

A:B =2:1 gets:a:b=9:5

12. If the trams ctrain every 4 minutes, we can find out by drawing a tracking diagram:

Two places The trains should start at the same time and 8 minutes apart

Suppose that the total distance is 1, then:

We know that the speed of the tram is 1/56, so the distance between the two trams coming in the opposite direction are 1/7

At that time, Xiao Zhang met an oncoming tram every 5 minutes

That is: 1/7 of the distance was covered by the tram and Xiao Zhang in 5 minutes. Xiao Zhang's speed can be calculated: (1/7)/5-1/56=3/280

Similarly: Xiao Wang encounters an oncoming tram every 6 minutes

Then the speed of Xiao Wang: (1/7)/6-1/56=1/168

Then the time Xiao Zhang and Xiao Wang were walking when they meet on the way is

1/(3/280+1/168)=840/14=60 points

I think I'm not the first to interpret this ideaand this question here

But I hope the poster can see it clearly

Consider it appropriate

I hope to adopt it

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I hope this can help you

A and B are trams. There are two departure stations, with a train leaving every 12 minutes and the tram travels 25 kilometers per hour. Please ask: (1) If Xiao Ming takes a tram from point A

The departure intervals are the same, then the distance between two adjacent trams in the same direction is the same

The sum of the speeds of the car and Xiao Zhang is 1/5

The sum of the speeds of the car and Xiao Wang is 1/6< /p>

The sum of the speeds of the two cars is 1/4< /p>

The sum of the speeds of Xiao Zhang and Xiao Wang is 1/5+1/6-1 /4= 7/60

The sum of the speeds of Xiao Zhang and Xiao Wang is 7/60 of the speed of the tram ÷(1/4÷2)=14/15

It takes two people toe meet: 70÷14/15=75 minutes

(1) 25×

=5÷50×60

=6 (minutes)

Answer: Him You will see a tram coming towards you every 6 minutes

(2)25×

=5÷30×60

=10 (minutes)

25×

=5÷20×60

=15 (minutes)

Answer: Every 10 minutes, he will see a tram coming towards him, and every 15 minutes, a tram will pass it from behind