LT1308? Schematic diagram that can be used for DC-DC boost chip? 3.7V? at 5V
Schematic diagram that can be used for DC-DC boost chip? - 12-27?15:14:56) Tags: Schematic ?boost?Boost?lt1308?Miscellaneous talk?
The LT1308 is a schematic diagram of a DC-DC boost chip from Linear Company. Its performance is. as follows:
1. Delivers 5V continuous current of 1A from a single lithium-ion battery
2. Provides 5V continuous current of 0.8A from four nickel-cadmium batteries in SEPIC
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3 mode. Amplification frequency: 600 kHz
4. Output voltage up to 34V
5. High load start possible
6. low load start (?LT1308A?)
7. Low Load Continuous Switching (?LT1308B?)
8. Low voltage drop: 2A, typical value 300mV
9, Pin-to-pin compatible upgrade to LT1308
10. Low quiescent current in shutdown mode: 1 mA (maximum)
11. Improved low battery detector accuracy: 200 mV±. 2%
Since the typical schematic diagram provided in his linear datasheet is not complete, the author draws another schematic diagram here. Physical electronic components connected according to this schematic diagram will be able to operate directly. Among them: SHDN is the start bit. It is estimated that the starting condition is that the level is greater than 1V, so it can be directly connected to the positive terminal of the input terminal or connected to a potentiometer (as shown below). The advantage of connecting to the potentiometer is to change the starting protection level of the input battery (such as Lithium battery). In addition, when the output current is large, the input capacitor should be as large as possible, preferably greater than 1000uF. The output capacitor must also be large enough, but it does notneed not necessarily be larger than the input capacitance. of FeedBack resistor is as shown in the figure below (309K can be used for 5V output, 100K resistor), if 309K resistor is hard to find and the voltage is not too strict, you can use a combination of 10K and 3.3K resistors to produce 5V, or you can use a 50K potentiometer. The FeedBack potential is 1.22V and the output voltage VOUT?=?1.22V(1?+? R1/R2). When a single-cell 1.5V alkaline or nickel input is used and the output voltage is 5V, the output current can provide a maximum value of approximately 100mA. If the load continues to increase, the output voltage will be significantly reduced and efficiency. will be weak. Using 3.7V lithium battery as input, when the output voltage is 5V, the maximum output current can reach about 1000mA, and the efficiency can reach eabout 85%.
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